(3х-2)(3х+2)(9х²+4)

To expand the given expression \((3x-2)(3x+2)(9x^2+4)\), we can use the distributive property to multiply the factors together.

First, multiply the first two binomials:

\((3x-2)(3x+2) = 9x^2 + 6x - 6x - 4 = 9x^2 - 4\)

Now, multiply the result by the third factor:

\((9x^2 - 4)(9x^2 + 4) = 81x^4 + 36x^2 - 36x^2 - 16\)

Simplify the expression:

\(81x^4 - 16\)

Therefore, the expanded form of \((3x-2)(3x+2)(9x^2+4)\) is \(81x^4 - 16\).