(3х-2)(3х+2)(9х²+4)

To expand the given expression \((3x-2)(3x+2)(9x^2+4)\), we can use the distributive property of multiplication:

First, expand the first two binomials: \((3x-2)(3x+2) = 9x^2 + 6x - 6x - 4 = 9x^2 - 4\)

Now, we have: \((9x^2 - 4)(9x^2 + 4)\)

Expanding these two binomials by applying the formula \((a+b)(a-b) = a^2 - b^2\), we get: \((9x^2)^2 - (4)^2 = 81x^4 - 16\)

Therefore, the expanded form of \((3x-2)(3x+2)(9x^2+4)\) is \(81x^4 - 16\).