(3х-2)(3х+2)(9х²+4)

To expand the given expression \((3x-2)(3x+2)(9x^2+4)\), we can apply the distributive property multiple times.

Let's first expand \((3x-2)(3x+2)\) using the formula \((a-b)(a+b) = a^2 - b^2\):

\((3x-2)(3x+2) = (3x)^2 - 2^2 = 9x^2 - 4\)

Now we have: \((9x^2 - 4)(9x^2+4)\)

Expanding this further:

\((9x^2 - 4)(9x^2+4) = 9x^2 * 9x^2 + 9x^2 * 4 - 4 * 9x^2 - 4 * 4\)

\(= 81x^4 + 36x^2 - 36x^2 - 16\)

\(= 81x^4 - 16\)

Therefore, the expanded form of the expression \((3x-2)(3x+2)(9x^2+4)\) is \(81x^4 - 16\)