Решите систему u+v^2=-3 u-5v=-3

To solve the system of equations, we'll use the method of substitution.

From the second equation, we can solve for u:

u = -3 + 5v

Now substitute this into the first equation:

-3 + 5v + v^2 = -3

Rearranging the equation:

v^2 + 5v = 0

Factoring:

v(v + 5) = 0

Setting each factor equal to zero:

v = 0 or v + 5 = 0

For v = 0:

u = -3 + 5(0) = -3

For v = -5:

u = -3 + 5(-5) = -3 - 25 = -28

Therefore, the solutions to the system of equations are:

(u, v) = (-3, 0) or (-28, -5)