M1=0.1kg m2=1500kg c1=c2=4200 Дж/кг*c=1=235°c t2= 30°c q1=? q2=?

To find q1 and q2, we can use the specific heat formula:

q = m * c * Δt

where: q = heat energy (in Joules) m = mass (in kg) c = specific heat capacity (in J/kg·°C) Δt = change in temperature (in °C)

For q1: m1 = 0.1 kg c1 = 4200 J/kg·°C Δt1 = (235°C - 30°C) = 205°C

q1 = m1 * c1 * Δt1 = 0.1 kg * 4200 J/kg·°C * 205°C = 86100 J or 86.1 kJ

q1 = 86.1 kJ

For q2: m2 = 1500 kg c2 = 4200 J/kg·°C Δt2 = (30°C - 235°C) = -205°C (negative because the temperature is decreasing)

q2 = m2 * c2 * Δt2 = 1500 kg * 4200 J/kg·°C * -205°C = -1291500000 J or -1291.5 MJ

q2 = -1291.5 MJ (negative sign indicates heat is leaving the system)

Therefore, q1 = 86.1 kJ q2 = -1291.5 MJ