M1=5кг c1=460Дж/кг*c1 m2=10kg c2=4200дж/кг*°c t1=126°c t2=153°c q=?

To find the amount of heat (q) transferred, we can use the equation:

q = m1 * c1 * (t2 - t1) + m2 * c2 * (t2 - t1)

Substituting the given values:

q = 5kg * 460J/kg*°C * (153°C - 126°C) + 10kg * 4200J/kg*°C * (153°C - 126°C)

q = 5kg * 460J/kg*°C * 27°C + 10kg * 4200J/kg*°C * 27°C

q = 62100J + 340200J

q ≈ 402,300J

Therefore, the amount of heat transferred is approximately 402,300J.