M1=5кг c1=460Дж/кг*c1 m2=10kg c2=4200дж/кг*°c t1=126°c t2=153°c q=?

To find the heat transfer (q), we can use the equation:

q = m1 * c1 * ΔT1 + m2 * c2 * ΔT2

Where: m1 = mass of the first object = 5 kg c1 = specific heat capacity of the first object = 460 J/(kg°C) ΔT1 = change in temperature of the first object = t2 - t1 = 153°C - 126°C = 27°C m2 = mass of the second object = 10 kg c2 = specific heat capacity of the second object = 4200 J/(kg°C) ΔT2 = change in temperature of the second object = t2 - t1 = 153°C - 126°C = 27°C

Plugging in the given values:

q = 5 kg * 460 J/(kg°C) * 27°C + 10 kg * 4200 J/(kg°C) * 27°C

q = 62100 J + 1134000 J

q ≈ 1196100 J

Therefore, the heat transfer (q) is approximately 1,196,100 J.