M1=5кг c1=460Дж/кг*c1 m2=10kg c2=4200дж/кг*°c t1=126°c t2=153°c q=?

To find the amount of heat transferred (q), you can use the formula:

q = m1 * c1 * (t2 - t1) + m2 * c2 * (t2 - t1)

where: m1 = mass of the first object (5kg) c1 = specific heat capacity of the first object (460 J/kg°C) m2 = mass of the second object (10kg) c2 = specific heat capacity of the second object (4200 J/kg°C) t1 = initial temperature (126°C) t2 = final temperature (153°C)

Substituting the given values into the formula:

q = 5kg * 460 J/kg°C * (153°C - 126°C) + 10kg * 4200 J/kg°C * (153°C - 126°C)

Now, let's calculate:

q =5 * 460 * (153-126) + 10 * 4200 * (153-126) q =5 * 460 * 27 + 10 * 4200 * 27 q =62100 + 1134000 q = 1196100 J

Therefore, the amount of heat transferred (q) is 1,196,100 Joules.