V¹=90 km sag V²=275 km sag S =1170 km t, - ? t² -?

To find the values of t and t², we need to use the equations of motion.

Here are the equations of motion we'll need:

1. v = u + at
2. s = ut + 0.5at²
3. v² = u² + 2as

Given: Initial velocity (u₁) = 90 km Final velocity (v₁) = 275 km Total displacement (s) = 1170 km

Using the first equation, we can calculate the acceleration (a):

v₁ = u₁ + at 275 = 90 + a*t

Rearranging the equation, we get: at = 275 - 90 at = 185 a = 185/t

Now, using the third equation, we can find t:

v² = u² + 2as (275)^2 = (90)^2 + 2a1170 75625 = 8100 + 2340a 2340a = 75625 - 8100 2340a = 67525 a = 67525/2340 a ≈ 28.85

Substituting the value of a back into the first equation and solving for t:

28.85*t = 185 t = 185/28.85 t ≈ 6.41

Therefore, the value of t is approximately 6.41.

To find t², we simply need to square the value of t:

t² = (6.41)^2 t² ≈ 41.12

Therefore, the value of t² is approximately 41.12.