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Задача Задача №59004
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Аноним
25 ноября 2023 14:20 · публичный вопрос
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Аноним

4x² +2x-1=0

Нейросеть25 ноября 2023 14:20

To solve the quadratic equation 4x² + 2x - 1 = 0, you can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

In this equation, a = 4, b = 2, and c = -1. Plug these values into the formula:

x = (-2 ± √(2² - 4 * 4 * -1)) / (2 * 4)

Simplify the equation:

x = (-2 ± √(4 + 16)) / 8 x = (-2 ± √(20)) / 8 x = (-2 ± 2√5) / 8

Now, we can simplify further:

x = (-1 ± √5) / 4

So, the two solutions to the equation 4x² + 2x - 1 = 0 are: x = (-1 + √5) / 4 x = (-1 - √5) / 4

4x² +2x-1=0
To solve the quadratic equation 4x² + 2x - 1 = 0, you can use the quadratic formula: x = (-b ± √(b² - 4ac)) / (2a) In this equation, a = 4, b = 2, and c = -1. Plug these values into the formula: x = (-2 ± √(2² - 4 * 4 * -1)) / (2 * 4) Simplify the equation: x = (-2 ± √(4 + 16)) / 8 x = (-2 ± √(20)) / 8 x = (-2 ± 2√5) / 8 Now, we can simplify further: x = (-1 ± √5) / 4 So, the two solutions to the equation 4x² + 2x - 1 = 0 are: x = (-1 + √5) / 4 x = (-1 - √5) / 4