Y=1,5x+4, y=1,5x-3,y=7

To find the values of x and y that satisfy all three equations, we need to solve the system of equations simultaneously.

Let's start by comparing the first two equations y = 1.5x + 4 and y = 1.5x - 3:

1.5x + 4 = 1.5x - 3

When we subtract 1.5x from both sides, the x term cancels out:

4 = -3

This equation is not possible since 4 cannot equal -3. Therefore, there is no solution that satisfies both equations y = 1.5x + 4 and y = 1.5x - 3 simultaneously.

Now let's compare the third equation y = 7 with the other two equations:

1.5x + 4 = 7

When we subtract 4 from both sides, we get:

1.5x = 7 - 4

1.5x = 3

To solve for x, divide both sides by 1.5:

x = 3/1.5

x = 2

Now substitute the value of x into any of the equations to find the value of y. Let's use y = 1.5x + 4:

y = 1.5(2) + 4

y = 3 + 4

y = 7

So, the values of x = 2 and y = 7 satisfy the third equation y = 7.

In summary, there is no solution that satisfies all three equations y = 1.5x + 4, y = 1.5x - 3, and y = 7 simultaneously. However, the values x = 2 and y = 7 satisfy the third equation y = 7.