F(x) = 5 arcsin x + 2 arccos x ; вычислите f'(1/2)

f'(1/2) = 5(1/√(1 - (1/2)^2)) + 2(-1/√(1 - (1/2)^2))

f'(1/2) = 5(1/√(1 - 1/4)) - 2/√(1 - 1/4)

f'(1/2) = 5(2/√3) - 2/√3

f'(1/2) = 10/√3 - 2/√3

f'(1/2) = (10 - 2)/√3

f'(1/2) = 8/√3

Ответ: f'(1/2) = 8/√3