Y=sin(cosx)

To find the derivative of the function y = sin(cosx), we can apply the chain rule.

Let's start by rewriting the function:

y = sin(cos(x))

Now, let's take the derivative of y with respect to x:

dy/dx = d/dx [sin(cos(x))]

Applying the chain rule, we differentiate the outer function with respect to the inner function and multiply it by the derivative of the inner function:

dy/dx = cos(cos(x)) * (-sin(x))

So, the derivative of y = sin(cosx) is dy/dx = -cos(cos(x)) * sin(x).

If you have any further questions, feel free to ask!