Дано: А(-4;-3), B(-1; 3), C(2; -2), D(0; 1). Найти (|2AB + 3CD|).

|2AB + 3CD| = |2(-1 + 4; 3 + 3) + 3(0 + 2; 1 - 2)| = |2(3; 6) + 3(2; -1)| = |(6; 12) + (6; -3)| = |(12; 9)| = √(12^2 + 9^2) = √(144 + 81) = √225 = 15.