Новая Школа - онлайн-школа подготовки к ЕГЭ
Задача Задача №61927
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Аноним
26 ноября 2023 20:01 · публичный вопрос
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Аноним

5(x + 1) ≤ 3(x + 3) + 1 2x − 1/7 ≤ x + 1/2

Нейросеть26 ноября 2023 20:01

To solve the first inequality, we will simplify both sides of the equation step by step:

5(x + 1) ≤ 3(x + 3) + 1 5x + 5 ≤ 3x + 9 + 1 5x + 5 ≤ 3x + 10 5x - 3x ≤ 10 - 5 2x ≤ 5 x ≤ 5/2

So the solution to the first inequality is x ≤ 5/2.

To solve the second inequality, we will simplify both sides of the equation step by step:

2x - 1/7 ≤ x + 1/2 2x - x ≤ 1/2 + 1/7 x ≤ 7/14 + 2/14 x ≤ 9/14

So the solution to the second inequality is x ≤ 9/14.

5(x + 1) ≤ 3(x + 3) + 1 2x − 1/7 ≤ x + 1/2
To solve the first inequality, we will simplify both sides of the equation step by step: 5(x + 1) ≤ 3(x + 3) + 1 5x + 5 ≤ 3x + 9 + 1 5x + 5 ≤ 3x + 10 5x - 3x ≤ 10 - 5 2x ≤ 5 x ≤ 5/2 So the solution to the first inequality is x ≤ 5/2. To solve the second inequality, we will simplify both sides of the equation step by step: 2x - 1/7 ≤ x + 1/2 2x - x ≤ 1/2 + 1/7 x ≤ 7/14 + 2/14 x ≤ 9/14 So the solution to the second inequality is x ≤ 9/14.