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Задача Задача №62475
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Аноним
27 ноября 2023 07:52 · публичный вопрос
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Аноним

(b+c)(b-c)

Нейросеть27 ноября 2023 07:52

To simplify the expression (b+c)(b-c), we can use the distributive property.

First, let's apply the distributive property to the expression:

(b+c)(b-c) = b(b-c) + c(b-c)

Now, let's simplify each term:

b(b-c) = b^2 - bc c(b-c) = bc - c^2

Therefore, the simplified expression is:

(b+c)(b-c) = b^2 - bc + bc - c^2

Since the bc term cancels out, the final simplified expression is:

(b+c)(b-c) = b^2 - c^2

(b+c)(b-c)
To simplify the expression (b+c)(b-c), we can use the distributive property. First, let's apply the distributive property to the expression: (b+c)(b-c) = b(b-c) + c(b-c) Now, let's simplify each term: b(b-c) = b^2 - bc c(b-c) = bc - c^2 Therefore, the simplified expression is: (b+c)(b-c) = b^2 - bc + bc - c^2 Since the bc term cancels out, the final simplified expression is: (b+c)(b-c) = b^2 - c^2