(sun 45⁰* tg 60⁰ + cos 45⁰*ctg 30⁰)- cos 60⁰

\( ( \sin 45^\circ \cdot \tan 60^\circ + \cos 45^\circ \cdot \cot 30^\circ) - \cos 60^\circ = \frac{\sqrt{2} \cdot \sqrt{3} + \frac{\sqrt{2}}{\sqrt{3}}}{1} - \frac{1}{2} = \sqrt{6} + \frac{2}{\sqrt{6}} - \frac{1}{2} \)

Ответ: \( \sqrt{6} + \frac{2}{\sqrt{6}} - \frac{1}{2} \)