5х-у=7 3х+2у=-1

To solve the system of equations:

5x - y = 7 ...(1) 3x + 2y = -1 ...(2)

We can use the method of elimination to eliminate one variable.

First, let's multiply equation (1) by 2:

2(5x - y) = 2(7) 10x - 2y = 14 ...(3)

Now, we can add equations (3) and (2) to eliminate the variable "y":

(10x - 2y) + (3x + 2y) = 14 + (-1) 10x - 2y + 3x + 2y = 13x + 0 13x = 13 x = 1

Now, substitute the value of x into either equation (1) or (2) to solve for y. Let's use equation (1):

5(1) - y = 7 5 - y = 7 -y = 7 - 5 -y = 2 y = -2

Therefore, the solution to the system of equations is x = 1 and y = -2.