5х-у=7 3х+2у=-1

To solve this system of equations, you can use the elimination method by multiplying the equations with coefficients that will allow you to cancel out one of the variables.

Let's start by multiplying both sides of the first equation by 2, and the second equation by 3 to make the coefficients of y the same:

2(5x - y) = 2(7) 3(3x + 2y) = 3(-1)

This simplifies to:

10x - 2y = 14 9x + 6y = -3

Now, we can add the equations together:

(10x - 2y) + (9x + 6y) = 14 + (-3)

This simplifies to:

19x + 4y = 11

Now we have a new equation with only x and y. We can solve for one variable and substitute it back into one of the original equations to find the value of the other variable.

Let's solve for y in terms of x:

4y = 11 - 19x y = (11 - 19x) / 4

Now we can substitute this expression for y back into the first equation:

5x - (11 - 19x)/4 = 7

Multiply through by 4 to clear the fraction:

20x - 11 + 19x = 28

Combine like terms:

39x - 11 = 28

Add 11 to both sides of the equation:

39x = 39

Divide both sides by 39:

x = 1

Now substitute this value back into the expression for y:

y = (11 - 19(1))/4 y = (11 - 19)/4 y = -2

Therefore, the solution to the system of equations is x = 1 and y = -2.