4х+у=10 х+3у=-3

To solve this system of equations, we can use the method of substitution.

From the first equation, we can solve for x: 4x + y = 10 4x = 10 - y x = (10 - y)/4

Substituting this value of x in the second equation: (10 - y)/4 + 3y = -3

Multiplying through by 4 to eliminate fractions: 10 - y + 12y = -12

Combining like terms: 11y = -22

Dividing both sides by 11: y = -2

Now, substituting this value of y back into the first equation: 4x + (-2) = 10 4x = 12 x = 3

Therefore, the solution to the system of equations is x = 3 and y = -2.