4х+у=10 х+3у=-3

To solve this system of equations, we can use the method of substitution or elimination. Let's solve it using substitution.

First, let's solve the first equation for x:

4x + y = 10

We can rearrange this equation to solve for x:

4x = 10 - y

x = (10 - y)/4

Now substitute this expression for x into the second equation:

x + 3y = -3

(10 - y)/4 + 3y = -3

Multiply through by 4 to get rid of the fraction:

10 - y + 12y = -12

Combine like terms:

11y + 10 = -12

Subtract 10 from both sides:

11y = -22

Divide by 11:

y = -2

Now substitute this value of y back into one of the original equations to solve for x. Let's use the first equation:

4x + y = 10

4x + (-2) = 10

4x - 2 = 10

Add 2 to both sides:

4x = 12

Divide by 4:

x = 3

Therefore, the solution to the system of equations is x = 3 and y = -2.