4х+у=10 х+3у=-3

To solve the system of equations:

4x + y = 10 --(1) x + 3y = -3 --(2)

We can solve this system using either the substitution method or the elimination method. Let's solve it using the elimination method:

Multiply equation (2) by 4 to make the coefficient of x in both equations the same:

4(x + 3y) = 4(-3) 4x + 12y = -12 --(3)

Now, we can subtract equation (3) from equation (1) to eliminate x:

(4x + y) - (4x + 12y) = 10 - (-12) 4x + y - 4x - 12y = 10 + 12 -11y = 22 y = -2

Substitute the value of y into equation (2) to solve for x:

x + 3(-2) = -3 x - 6 = -3 x = -3 + 6 x = 3

Therefore, the solution to the system of equations is x = 3 and y = -2.