4х+у=10 х+3у=-3

One way to solve this system of equations is by using the method of substitution.

From the first equation, we can solve for x in terms of y: 4x + y = 10 4x = 10 - y x = (10 - y)/4

Now we substitute this expression for x in the second equation: x + 3y = -3 [(10 - y)/4] + 3y = -3

Next, we simplify the equation: 10 - y + 12y = -12 11y + 10 = -12 11y = -22 y = -2

Now we substitute this value of y back into the first equation to solve for x: 4x + y = 10 4x + (-2) = 10 4x - 2 = 10 4x = 12 x = 3

The solution to the system of equations is x = 3 and y = -2.