Задача Задача №637242
А
А
sin(2tg(α)) = 2sin(α)cos(α)
cos(α) = 1/2
sin(α) = √(1 - (cos(α))^2) = √(1 - (1/2)^2) = √(1 - 1/4) = √3/2
Теперь мы можем рассчитать sin(2tg(α)):
sin(2tg(α)) = 2 * (sin(α)) * (cos(α)) = 2 * (√3/2) * (1/2) = √3/2
sin(2tg(α)) = 2sin(α)cos(α)
cos(α) = 1/2
sin(α) = √(1 - (cos(α))^2) = √(1 - (1/2)^2) = √(1 - 1/4) = √3/2
Теперь мы можем рассчитать sin(2tg(α)):
sin(2tg(α)) = 2 * (sin(α)) * (cos(α)) = 2 * (√3/2) * (1/2) = √3/2