4х+у=10 х+3у=-3

To solve the system of equations:

4х + у = 10 ......(1) х + 3у = -3 ......(2)

We can solve this system of equations using the substitution method or the elimination method. Let's use the elimination method:

Multiply equation (2) by -4 to eliminate the x term:

-4(х + 3у) = -4(-3) -4х - 12у = 12

Now, add equation (1) to the new equation:

4х + у + (-4х - 12у) = 10 + 12 (4х - 4х) + (у - 12у) = 22 -11у = 22

Divide both sides by -11:

у = -2

Now, substitute the value of у in any of the original equations. Let's use equation (1):

4х + (-2) = 10 4х - 2 = 10 4х = 10 + 2 4х = 12

Divide both sides by 4:

х = 3

So, the solution to the system of equations is х = 3 and у = -2.