4х+у=10 х+3у=-3

To solve this system of equations, you can use the substitution method.

Let's solve equation 2 for x:

x + 3y = -3 x = -3 - 3y

Now substitute this expression for x into equation 1:

4(-3 - 3y) + y = 10

Simplify and solve for y:

-12 - 12y + y = 10 -11y = 22 y = -2

Now substitute this value of y back into equation 2 to find x:

x + 3(-2) = -3 x - 6 = -3 x = 3

Therefore, the solution to the system of equations is x = 3 and y = -2.