4х+у=10 х+3у=-3

To solve this system of equations, you can use either substitution or elimination method. Let's start with the elimination method.

First, we can multiply the second equation by 4 to make the coefficients of x the same in both equations:

4(x + 3y) = 4(-3) 4x + 12y = -12

Next, we can subtract the first equation from this new equation to eliminate x:

(4x + 12y) - (4x + y) = -12 - 10 11y = -22

Now, we can solve for y:

y = -22 / 11 y = -2

Substitute this value of y back into the first equation to find x:

4x + (-2) = 10 4x - 2 = 10 4x = 12 x = 12 / 4 x = 3

Therefore, the solution to the system of equations is x = 3 and y = -2.