0,5у^3-0, 5у(у+1) (у-3) =7

To solve the equation 0.5y^3 - 0.5y(y+1)(y-3) =7, follow these steps:

Step 1: Distribute the -0.5y to the terms within the parentheses: 0.5y^3 - 0.5y^2 - 0.5y(y-3) = 7

Step 2: Distribute the -0.5y to the terms inside the second set of parentheses: 0.5y^3 - 0.5y^2 - 0.5y^2 + 1.5y = 7

Step 3: Combine like terms: 0.5y^3 - y^2 + 1.5y = 7

Step 4: Move all terms to one side to form a quadratic equation: 0.5y^3 - y^2 + 1.5y - 7 = 0

This cubic equation can be solved graphically or using numerical methods.