√x=2/7 x^2=16

To solve for x, we can square both sides of the equation √x = 2/7:

(√x)^2 = (2/7)^2 x = (2/7)^2 x = 4/49

So, x = 4/49.

To solve for x^2 = 16, we can take the square root of both sides of the equation:

√(x^2) = √16 |x| = 4

Since both the positive and negative square roots of 16 are 4, we need to consider both cases:

Case 1: x = 4 Case 2: x = -4

Therefore, the solutions to x^2 = 16 are x = 4 and x = -4.