To find AK, we need to use the Pythagorean theorem.
In rectangle ABCD, we have a right triangle AKD with sides AK, KD, and AD. Since KD = 9 cm, we need to find the length of AD.
Given that KV = 7 cm and KS = 9 cm, we can deduce that the triangle KVS is a right triangle.
Using the Pythagorean theorem in triangle KVS, we have:
KV^2 + KS^2 = VS^2 (7 cm)^2 + (9 cm)^2 = VS^2 49 cm^2 + 81 cm^2 = VS^2 130 cm^2 = VS^2
Therefore, VS = √130 cm.
Now, in triangle KAD, we have:
AK^2 + KD^2 = AD^2 AK^2 + (9 cm)^2 = AD^2 AK^2 + 81 cm^2 = AD^2
But we know that AD = KS + VS.
So, KS + VS = √130 cm + VS = AD.
Therefore,
AK^2 + 81 cm^2 = (√130 cm + VS)^2 AK^2 + 81 cm^2 = (√130 cm)^2 + 2 * √130 cm * VS + VS^2 AK^2 = 130 cm + 2 * √130 cm * √130 cm + VS^2 - 81 cm^2 AK^2 = 130 cm + 260 cm + VS^2 - 81 cm^2 AK^2 = 389 cm + VS^2 - 81 cm^2 AK^2 = 308 cm + VS^2
Substituting the value of VS^2 = 130 cm^2, we get:
AK^2 = 308 cm + 130 cm^2 AK^2 = 308 cm + 130 cm^2 AK^2 = 438 cm AK = √438 cm
Therefore, AK ≈ 20.93 cm.
