Cu(OH)²+HNO³

The reaction between Cu(OH)² and HNO³ can be written as:

Cu(OH)² + 2HNO³ -> Cu(NO³)² + 2H²O

In this reaction, copper(II) hydroxide (Cu(OH)²) reacts with nitric acid (HNO³) to form copper(II) nitrate (Cu(NO³)²) and water (H²O).

The balanced equation shows that 1 mole of Cu(OH)² reacts with 2 moles of HNO³ to produce 1 mole of Cu(NO³)² and 2 moles of H²O.