Sure! I will fill in the table and plot the graph for the given equations y = -1/3x + 2 and y = 1/3x - 2.
First, let's create a table of values by substituting different x values and calculating the corresponding y values for each equation.
For y = -1/3x + 2: x = -3, y = -1/3(-3) + 2 = 3 + 2 = 5 x = -2, y = -1/3(-2) + 2 = 2/3 + 2 = 8/3 x = -1, y = -1/3(-1) + 2 = 1/3 + 2 = 7/3 x = 0, y = -1/3(0) + 2 = 2 x = 1, y = -1/3(1) + 2 = -1/3 + 2 = 5/3 x = 2, y = -1/3(2) + 2 = -2/3 + 2 = 4/3 x = 3, y = -1/3(3) + 2 = -3/3 + 2 = 1/3
For y = 1/3x - 2: x = -3, y = 1/3(-3) - 2 = -1 - 2 = -3 x = -2, y = 1/3(-2) - 2 = -2/3 - 2 = -2 2/3 x = -1, y = 1/3(-1) - 2 = -1/3 - 2 = -2 1/3 x = 0, y = 1/3(0) - 2 = -2 x = 1, y = 1/3(1) - 2 = 1/3 - 2 = -5/3 x = 2, y = 1/3(2) - 2 = 2/3 - 2 = -1 1/3 x = 3, y = 1/3(3) - 2 = 1 - 2 = -1
Now, let's plot the points on a graph:
The graph will have x-values on the x-axis and y-values on the y-axis.
For the equation y = -1/3x + 2, the points are: (-3, 5), (-2, 8/3), (-1, 7/3), (0, 2), (1, 5/3), (2, 4/3), (3, 1/3).
For the equation y = 1/3x - 2, the points are: (-3, -3), (-2, -8/3), (-1, -2 1/3), (0, -2), (1, -5/3), (2, -1 1/3), (3, -1).
Now, let's plot the points and draw the lines:
Here is the graph:
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I hope this helps! Let me know if you have any other questions.
