Задача Задача №676602
А
А
Δ φ = ∇ 2 φ = ( ∂ 2 φ ∂ x 2 ) + ( ∂ 2 φ ∂ y 2 ) + ( ∂ 2 φ ∂ z 2 ) Δ φ = ( -y sin(x) ) + ( 2z ) + 0 Δ φ = -2sin(π/6) + 4 = -2(1/2) + 4 = 3
Ответ: 3
Δ φ = ∇ 2 φ = ( ∂ 2 φ ∂ x 2 ) + ( ∂ 2 φ ∂ y 2 ) + ( ∂ 2 φ ∂ z 2 ) Δ φ = ( -y sin(x) ) + ( 2z ) + 0 Δ φ = -2sin(π/6) + 4 = -2(1/2) + 4 = 3
Ответ: 3
