Задача Задача №693436
А
А
Решение:
sin2x + sin4x = sin3x
sin2x + 2sin2xcos2x = 2sin1.5xcos1.5x
sin2x + 2sin2xcos2x = 2sin1.5x(cos0.5x + sin0.5x)
sin2x + 2sin2xcos2x = 2sin1.5xcos(90 - 0.5x)
sin2x + 2sin2xcos2x = 2sin1.5xsin0.5x
sin2x + 2sin2xcos2x = sin2x + sinx
2sin2xcos2x = sinx
sin4x = sinx
4x = x + 2πn
3x = 2πn
x = 2πn/3.
