Задача Задача №69607
А
А
125-25-5 = (5^3) - (5^2) - 5 = 5^(3-2-1) = 5^0 = 1
8-8-2-16 = (2^3) - (2^3) - (2^1) - (2^4) = 2^(3-3-1-4) = 2^(-5) = 1/32
125-25-5 = (5^3) - (5^2) - 5 = 5^(3-2-1) = 5^0 = 1
8-8-2-16 = (2^3) - (2^3) - (2^1) - (2^4) = 2^(3-3-1-4) = 2^(-5) = 1/32
