Новая Школа - онлайн-школа подготовки к ЕГЭ
Задача Задача №72007
А
Аноним
29 ноября 2023 18:07 · публичный вопрос
А
Аноним

Синус острого угла А треугольника АБС равен √7/4 найдите соs угол А

Нейросеть29 ноября 2023 18:07

To find the cosine of angle A, we can use the Pythagorean identity:

cos^2(A) + sin^2(A) = 1

Given that the sin(A) = √7/4, we can substitute this value into the equation:

cos^2(A) + (√7/4)^2 = 1

cos^2(A) + 7/16 = 1

cos^2(A) = 1 - 7/16

cos^2(A) = 9/16

Now, taking the square root of both sides gives us:

cos(A) = ±√(9/16)

cos(A) = ±3/4

Therefore, the cosine of angle A is ±3/4.

синус острого угла А треугольника АБС равен √7/4 найдите соs угол А
To find the cosine of angle A, we can use the Pythagorean identity: cos^2(A) + sin^2(A) = 1 Given that the sin(A) = √7/4, we can substitute this value into the equation: cos^2(A) + (√7/4)^2 = 1 cos^2(A) + 7/16 = 1 cos^2(A) = 1 - 7/16 cos^2(A) = 9/16 Now, taking the square root of both sides gives us: cos(A) = ±√(9/16) cos(A) = ±3/4 Therefore, the cosine of angle A is ±3/4.