Задача Задача №810413
А
А
3x^2 + 7 = 12x - 7
3x^2 - 12x + 14 = 0
x = (12 ± √(12^2 - 4314)) / 6
x = (12 ± √(144 - 168)) / 6
x = (12 ± √(-24)) / 6
x = (12 ± 2√6i) / 6
x = 2 ± √6i
3x^2 + 7 = 12x - 7
3x^2 - 12x + 14 = 0
x = (12 ± √(12^2 - 4314)) / 6
x = (12 ± √(144 - 168)) / 6
x = (12 ± √(-24)) / 6
x = (12 ± 2√6i) / 6
x = 2 ± √6i
