3x + y = 7; 2x - y = 7

To solve this system of equations, we can use the method of elimination or substitution. Let's use substitution.

From the first equation, we can rearrange it to solve for y: y = 7 - 3x

Now substitute this value of y into the second equation: 2x - (7 - 3x) = 7

Simplify the equation: 2x - 7 + 3x = 7 5x - 7 = 7

Add 7 to both sides of the equation: 5x = 14

Divide both sides of the equation by 5: x = 14/5

Now substitute this value of x back into the first equation to find y: 3(14/5) + y = 7

Multiply 3 and (14/5): 42/5 + y = 7

Subtract 42/5 from both sides of the equation: y = 7 - 42/5

Multiply 7 by 5 to get a common denominator: y = (35/5) - (42/5)

Combine the fractions: y = -7/5

Therefore, the solution to the system of equations is x = 14/5 and y = -7/5.