Na20+SO3^Na2So3+Q степень окисления

The given equation is not balanced, but assuming it is meant to represent a redox reaction, we can determine the change in oxidation state for the elements involved.

To find the change in oxidation state, we assign oxidation numbers to each element:

Na20: The oxidation state of oxygen (O) is -2, and since Na20 is neutral, the oxidation state of sodium (Na) is +2.

SO3: The oxidation state of oxygen (O) is -2, and since SO3 is neutral, the oxidation state of sulfur (S) is +6.

Na2SO3: The oxidation state of oxygen (O) is again -2, and since Na2SO3 is neutral, the sum of the oxidation states of sodium (Na) and sulfur (S) must equal zero. Therefore, the oxidation state of sulfur (S) in Na2SO3 is +4.

From this analysis, we can see that the oxidation state of sulfur (S) decreases from +6 in SO3 to +4 in Na2SO3. In other words, the oxidation state of sulfur (S) is reduced by 2.