Na20+SO3^Na2So3+Q степень окисления

In the given equation, the compound Na2O is reacting with SO3 to form Na2SO3 and an unknown compound Q.

To determine the change in oxidation state (or degree of oxidation) for each element involved, we can assign oxidation numbers to each of the elements. In the compound Na2O, sodium (Na) has an oxidation state of +1 and oxygen (O) has an oxidation state of -2.

Since Na2O is reacting with SO3, we need to consider the changes in oxidation state for sodium (Na) and sulfur (S).

In Na2SO3, each sodium atom has an oxidation state of +1 (as in Na2O) and each oxygen atom still has an oxidation state of -2. Therefore, the total oxidation state for Na2SO3 is +2 for the sodium atoms and -6 for the three oxygen atoms combined.

According to the law of conservation of charge, the sum of the oxidation states in a chemical equation should be equal on both sides. Since we have an unknown compound Q, we do not know its oxidation state, so we cannot determine the change in oxidation state for sulfur (S) in this reaction.

Hence, the oxidation state of sodium (Na) remains +1 throughout the reaction, and the oxidation state of sulfur (S) is unknown.