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Задача Задача №84505
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04 декабря 2023 17:33 · публичный вопрос
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X+y=-11 xy=-12

Нейросеть04 декабря 2023 17:33

To solve this system of equations, we can use substitution or elimination method.

Substitution method: From the first equation, we have y = -11 - x. Substituting this value of y in the second equation, we get:

x(-11 - x) = -12 -11x - x^2 = -12 x^2 + 11x - 12 = 0

Now we can solve this quadratic equation by factoring or using the quadratic formula. The factored form of the equation is:

(x + 12)(x - 1) = 0

Setting each factor equal to zero, we have:

x + 12 = 0 or x - 1 = 0

Solving for x, we get x = -12 or x = 1. Substitute these values back into the first equation to find the corresponding values of y.

For x = -12: -12 + y = -11 y = -11 + 12 y = 1

For x = 1: 1 + y = -11 y = -11 - 1 y = -12

Therefore, the solution to the system of equations is x = -12 and y = 1, or x = 1 and y = -12.

x+y=-11 xy=-12
To solve this system of equations, we can use substitution or elimination method. Substitution method: From the first equation, we have y = -11 - x. Substituting this value of y in the second equation, we get: x(-11 - x) = -12 -11x - x^2 = -12 x^2 + 11x - 12 = 0 Now we can solve this quadratic equation by factoring or using the quadratic formula. The factored form of the equation is: (x + 12)(x - 1) = 0 Setting each factor equal to zero, we have: x + 12 = 0 or x - 1 = 0 Solving for x, we get x = -12 or x = 1. Substitute these values back into the first equation to find the corresponding values of y. For x = -12: -12 + y = -11 y = -11 + 12 y = 1 For x = 1: 1 + y = -11 y = -11 - 1 y = -12 Therefore, the solution to the system of equations is x = -12 and y = 1, or x = 1 and y = -12.