4х^2+9х+5=0

To solve the quadratic equation 4x^2 + 9x + 5 = 0, we can use the quadratic formula.

The quadratic formula states:

x = (-b ± √(b^2 - 4ac)) / (2a)

In this case, a = 4, b = 9, and c = 5.

Plugging these values into the formula, we get:

x = (-9 ± √(9^2 - 4(4)(5))) / (2(4))

Simplifying further:

x = (-9 ± √(81 - 80)) / 8 x = (-9 ± √1) / 8

Now we can calculate the two possible values for x:

x1 = (-9 + 1) / 8 = -8/8 = -1 x2 = (-9 - 1) / 8 = -10/8 = -5/4

Therefore, the solutions to the quadratic equation 4x^2 + 9x + 5 = 0 are x = -1 and x = -5/4.