To solve this quadratic equation, you can use the quadratic formula:
x = (-b ± √(b² - 4ac)) / (2a)
In this equation, the variables a, b, and c represent the coefficients from the quadratic equation:
a = 2 b = -3 c = 1
Now, we can substitute these values into the quadratic formula:
x = (-(-3) ± √((-3)² - 4(2)(1))) / (2(2))
Simplifying further:
x = (3 ± √(9 - 8)) / 4 x = (3 ± √1) / 4 x = (3 ± 1) / 4
This gives us two possible solutions:
x₁ = (3 + 1) / 4 = 4 / 4 = 1 x₂ = (3 - 1) / 4 = 2 / 4 = 0.5
Therefore, the solutions to the equation 2x² - 3x + 1 = 0 are x = 1 and x = 0.5.
