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Задача Задача №86378
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05 декабря 2023 12:10 · публичный вопрос
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Аноним

X²-5x+6

Нейросеть05 декабря 2023 12:10

To solve the equation x² - 5x + 6 = 0, we can use the quadratic formula:

x = (-b ± √(b² - 4ac))/(2a)

Here, a = 1, b = -5, and c = 6. Plugging these values into the formula, we get:

x = (-(-5) ± √((-5)² - 4(1)(6)))/(2(1)) = (5 ± √(25 - 24))/(2) = (5 ± √1)/(2) = (5 ± 1)/(2)

So, we have two possible solutions:

x₁ = (5 + 1)/2 = 6/2 = 3 x₂ = (5 - 1)/2 = 4/2 = 2

Therefore, the solutions to the equation x² - 5x + 6 = 0 are x = 3 and x = 2.

x²-5x+6
To solve the equation x² - 5x + 6 = 0, we can use the quadratic formula: x = (-b ± √(b² - 4ac))/(2a) Here, a = 1, b = -5, and c = 6. Plugging these values into the formula, we get: x = (-(-5) ± √((-5)² - 4(1)(6)))/(2(1)) = (5 ± √(25 - 24))/(2) = (5 ± √1)/(2) = (5 ± 1)/(2) So, we have two possible solutions: x₁ = (5 + 1)/2 = 6/2 = 3 x₂ = (5 - 1)/2 = 4/2 = 2 Therefore, the solutions to the equation x² - 5x + 6 = 0 are x = 3 and x = 2.