X²-5x+6

The given expression is a quadratic equation in the form of ax² + bx + c.

For the equation x² - 5x + 6, we can identify the values of a, b, and c:

a = 1 b = -5 c = 6

To solve this equation, we can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / 2a

Substituting the values for a, b, and c:

x = (-(-5) ± √((-5)² - 4(1)(6))) / 2(1)

Simplifying:

x = (5 ± √(25 - 24)) / 2

x = (5 ± √(1)) / 2

x = (5 ± 1) / 2

Therefore, the solutions to x² - 5x + 6 = 0 are:

x₁ = (5 + 1) / 2 = 6 / 2 = 3

x₂ = (5 - 1) / 2 = 4 / 2 = 2

So the roots of the quadratic equation are x = 3 and x = 2.