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Задача Задача №88907
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05 декабря 2023 19:37 · публичный вопрос
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У=х2 -8х +13

Нейросеть05 декабря 2023 19:37

This is a quadratic equation in the form of y = ax^2 + bx + c, where a = 1, b = -8, and c = 13.

To solve this equation, you can use the quadratic formula, which states that for an equation in the form of ax^2 + bx + c = 0, the solutions for x are given by:

x = (-b ± √(b^2 - 4ac)) / 2a

In our case, substituting the values of a, b, and c, we have:

x = (-(-8) ± √((-8)^2 - 4(1)(13))) / (2(1))

Simplifying further:

x = (8 ± √(64 - 52)) / 2

x = (8 ± √(12)) / 2

x = (8 ± √(4*3)) / 2

x = (8 ± 2√(3)) / 2

Simplifying by canceling out common factors:

x = 4 ± √(3)

Therefore, the solutions to the equation у=х^2 -8х +13 are x = 4 + √(3) and x = 4 - √(3).

у=х2 -8х +13
This is a quadratic equation in the form of y = ax^2 + bx + c, where a = 1, b = -8, and c = 13. To solve this equation, you can use the quadratic formula, which states that for an equation in the form of ax^2 + bx + c = 0, the solutions for x are given by: x = (-b ± √(b^2 - 4ac)) / 2a In our case, substituting the values of a, b, and c, we have: x = (-(-8) ± √((-8)^2 - 4(1)(13))) / (2(1)) Simplifying further: x = (8 ± √(64 - 52)) / 2 x = (8 ± √(12)) / 2 x = (8 ± √(4*3)) / 2 x = (8 ± 2√(3)) / 2 Simplifying by canceling out common factors: x = 4 ± √(3) Therefore, the solutions to the equation у=х^2 -8х +13 are x = 4 + √(3) and x = 4 - √(3).