X^2+3x+5

The given expression is a quadratic equation. To solve it, we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

In this case, a = 1, b = 3, and c = 5. Plugging these values into the quadratic formula, we get:

x = (-3 ± √(3^2 - 4(1)(5))) / (2(1))

Simplifying further:

x = (-3 ± √(9 - 20)) / 2

x = (-3 ± √(-11)) / 2

Since the square root of a negative number is not a real number, we can conclude that the given equation has no real solutions.