X^2+3x+5 = 0

To solve the quadratic equation x^2 + 3x + 5 = 0, you can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

In this case, a = 1, b = 3, and c = 5, so substituting these values into the formula:

x = (-3 ± √(3^2 - 4(1)(5))) / (2(1))

x = (-3 ± √(9 - 20)) / 2

x = (-3 ± √(-11)) / 2

Since the term inside the square root is negative, there is no real solution to this equation. The solutions are complex numbers.