To solve the equation (5/x-1) + (30/x+1) = 5, we can start by finding a common denominator for the fractions. In this case, the common denominator is (x - 1)(x + 1).
So, let's rewrite the equation with the common denominator:
(5(x + 1) + 30(x - 1)) / (x - 1)(x + 1) = 5
Expanding and simplifying the equation, we have:
(5x + 5 + 30x - 30) / (x - 1)(x + 1) = 5
(35x - 25) / (x - 1)(x + 1) = 5
Now, let's multiply both sides of the equation by the common denominator:
(35x - 25) = 5(x - 1)(x + 1)
Let's distribute on the right side of the equation:
35x - 25 = 5(x^2 - 1)
Expand further:
35x - 25 = 5x^2 - 5
Now, let's bring all terms to one side of the equation:
5x^2 - 35x + 5 - 25 = 0
5x^2 - 35x - 20 = 0
Divide the equation by 5 to simplify:
x^2 - 7x - 4 = 0
The equation is now in standard form. To solve it, we can use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / 2a
For this equation, a = 1, b = -7, and c = -4.
x = (-(-7) ± √((-7)^2 - 4(1)(-4))) / (2(1))
x = (7 ± √(49 + 16)) / 2
x = (7 ± √65) / 2
Therefore, the solutions to the equation are x = (7 + √65) / 2 and x = (7 - √65) / 2.
