(x+2)²+(y-3)=0

To solve the equation, we can start by expanding the squared term:

(x+2)² = (x+2)(x+2) = x(x+2) + 2(x+2) = x² + 2x + 2x + 4 = x² + 4x + 4

Now let's substitute this into the equation:

(x+2)² + (y-3) = 0 (x² + 4x + 4) + (y-3) = 0 x² + 4x + 4 + y - 3 = 0 x² + 4x + y + 1 = 0

So, the equation simplifies to x² + 4x + y + 1 = 0.